pit.volume(level=100)['below'] - pit.volume(level=50)['below']
Yes it can. You could just digitize a polygon around your open pit. Supposing the surrounding polygon is pit then difference in volume between level 100 ft and 50 ft would be (supposing elevation units are feet):Code: [Select]pit.volume(level=100)['below'] - pit.volume(level=50)['below']1st example shows volume of pile between levels 335 m and 345 m. Since it is a pile I use 'above' instead of 'below'...53760.9 m32nd example show volume between levels 131 m and 128 m for a quarry pit 2879.13 m3
How or where do you specify the two different elevations that you are trying to measure between?